Forgot password?
 Register account
View 252|Reply 0

[数列] 周期3 线性递推$a_n=-a_{n-1}-a_{n-2}$

[Copy link]

3152

Threads

7905

Posts

610K

Credits

Credits
64068
QQ

Show all posts

hbghlyj Posted 2023-4-20 17:20 |Read mode
$$a_n=(-2)^{2-n} \sum_{k=0}^{\lfloor\frac{n+1}{2}\rfloor}(-3)^{k-1}\left(\frac{2k}{n+1}-\frac{3}{4}\right) \binom{n+1}{2k}$$求证:$a_n=-a_{n-1}-a_{n-2}$
$n$01234567891011121314151617181920
$a_n$1-101-101-101-101-101-101-10

$a_n=(-1)^n\left(\frac1{\sqrt3}\sin\left(π n\over3\right) +\cos\left(π n\over3\right)\right)$

Mobile version|Discuz Math Forum

2025-6-4 21:22 GMT+8

Powered by Discuz!

× Quick Reply To Top Edit