Forgot password?
 Create new account
View 126|Reply 1

$ℝP^n$微分同胚于 迹1的幂等对称阵组成的$ℝ^{(n+1)^2}$子流形

[Copy link]

3147

Threads

8493

Posts

610K

Credits

Credits
66163
QQ

Show all posts

hbghlyj Posted at 2023-5-14 09:12:03 |Read mode
Wikipedia
The projective $n$-space is in fact diffeomorphic to the submanifold of $ℝ^{(n+1)^2}$ consisting of all symmetric $(n + 1) × (n + 1)$ matrices of trace 1 that are also idempotent linear transformations.
如何证明?

48

Threads

969

Posts

110K

Credits

Credits
14870
QQ

Show all posts

Czhang271828 Posted at 2023-5-14 13:55:55
A symmetric idenpotent matrix of trace $k$ is nothing but a projection onto an  $k$-dimensional space (obvious, or found in the textbook of 丘维声 (maybe)). Hence the Grassmannian $G_{n}(\mathbb F^m)$, consisting of $m$-dimensional linear subspaces of $\mathbb F^n$, is isomorphic to the manifold of symmetric idenpotent matrices in $\mathbb F^{n\times n}$ of trace $m$. Here $G_{n+1}(\mathbb F^1)=\mathbb P_{\mathbb F}^n$.

手机版Mobile version|Leisure Math Forum

2025-4-20 22:20 GMT+8

Powered by Discuz!

× Quick Reply To Top Return to the list