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Simultaneous triangularisability

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hbghlyj Posted at 2023-5-27 05:22:20 |Read mode
Last edited by hbghlyj at 2023-5-27 14:40:00$[A,B]=AB-BA$. 若$A,B$可同时上三角化,且$[A,B]^2=0$,则$[A,B]=0$.

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Czhang271828 Posted at 2023-5-27 20:40:08
链接中想说的是二维情况. 一般来说是错的, 例如 $A=\begin{pmatrix}0&1&0\\0&0&0\\0&0&0\end{pmatrix}$, $B=\begin{pmatrix}0&0&0\\0&0&1\\0&0&0\end{pmatrix}$, 则 $AB-BA=\begin{pmatrix}0&0&1\\0&0&0\\0&0&0\end{pmatrix}$.

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2025-4-20 22:04 GMT+8

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