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[几何] 一个n维超立方体可以分解成x个子n维超立方体,如何求x的解集?

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lihpb Posted at 2024-10-3 16:14:36 |Read mode
各个子n维超立方体可以大小不一


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Czhang271828 Posted at 2024-10-5 17:58:43
$n=3$ 的结果见此处.

依照归纳, 若能分成 $m$ 个子超立方体或是 $n$ 个子超立方体, 则 $m+n-1$ 也是可行的解. 这表明存在 $N\in \mathbb N_+$, 使得 $n>N$ 都是解. 这应该是个没有解析解的问题, 可以按图索骥地找下去.

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2025-4-23 03:05 GMT+8

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