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一个超越函数的不等式链

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青青子衿 Posted at 2013-12-7 16:51:00 |Read mode

$x\in R_+,e^x+ln(x+1)-2x-1<e^x-x-1<e^x-ln(x+1)-1<(e^x-1)ln(x+1)$

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其妙 Posted at 2013-12-7 17:06:16

回复 1# 青青子衿

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