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original poster: aishuxue

[组合] 一道模拟考试中的计数问题

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乌贼 posted 2014-1-14 17:57
回复 20# kuing
我又回到人教群看,也是$\dfrac{a_{2k-1}}{a_{2k}}\ne-1$

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kuing posted 2014-1-14 18:10
回复  kuing
我又回到人教群看,也是$\dfrac{a_{2k-1}}{a_{2k}}\ne-1$
乌贼 发表于 2014-1-14 17:57
无语了,我不是说没有这个式子
“存在 $1\leqslant k\leqslant m$,使得 $a_{2k-1}/a_{2k}\ne1$”
重点是存在,存在,懂吗?
只要有一个 $k$ 使得 $a_{2k-1}/a_{2k}\ne1$ 就够了,其他的可以全是 $a_{2k-1}/a_{2k}=1$。

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乌贼 posted 2014-1-14 18:13
回复 22# kuing
愚钝

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kuing posted 2014-1-14 18:17
回复 23# 乌贼

再仔细读题,理解一下题目的意思先。[大兵]我煮饭去了

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乌贼 posted 2014-1-14 18:21
回复 24# kuing
我明白了,只要有一个就行。我原来认为必须全部,唉……

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kuing posted 2014-1-15 16:02
回复 14# kuing

话说突然发现忘记设置缩进……

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爪机专用 posted 2014-1-17 08:57
标答是怎样嘀??

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