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[函数] 已知函数$f(x)=2x-x^2$,函数$g(x)=\sin(\frac{πx}{2})$

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青青子衿 Posted 2013-10-2 10:20 |Read mode
已知函数$f(x)=2x-x^2$,函数$g(x)=sin(\dfrac{πx}{2})$,证明:
ⅰ.当$x∈[0,2]$时,$f(x)\geqslant g(x)$
ⅱ. 当$x∈[0,2]$时,$f(x)\leqslant\sqrt{g(x)}$
ⅲ. 当$x∈[0,2]$时,$\sqrt{f(x)}\leqslant g(\sqrt{x})$

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其妙 Posted 2013-10-2 16:51
牛笔!

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 Author| 青青子衿 Posted 2016-8-18 18:01
回复 1# 青青子衿

已知函数$f(x)=2x-x^2$,函数$g(x)=sin(\dfrac{πx}{2})$,证明:
ⅰ.当$x∈[0,2]$时,$f(x)\geqslant g(x)$
ⅱ. 当$x∈[0,2]$时,$f(x)\leqslant\sqrt{g(x)}$
ⅲ. 当$x∈[0,2]$时,$\sqrt{f(x)}\leqslant g(\sqrt{x})$
...
青青子衿 发表于 2013-10-2 10:20
这个题与本征函数有什么样的联系?
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