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[数列] 三道数列题

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青青子衿 Posted at 2013-10-13 13:52:32 |Read mode
已知$a_1=a,a_2=b,a_{n+1}-a_{n-1}=1,a_n=?$
已知$a_1=1,a_2=1,a_{n+1}-a_{n-1}=n,a_n=?$
已知$a_1=1,a_2=1,n^2(a_n-a_{n-1}-a_{n+1})+n(a_{n+1}-a_{n-1})-a_n=0,a_{100}=?$

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其妙 Posted at 2013-10-13 14:00:54
回复 1# 青青子衿
第一二问是可做的,第三问不动笔是不行的,
妙不可言,不明其妙,不着一字,各释其妙!

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战巡 Posted at 2013-10-13 14:36:35
回复 1# 青青子衿


前两问太无聊,懒得搞了
第三个...
\[a_{n+1}n(n-1)=(n^2-1)a_{n}-n(n+1)a_{n-1}\]
\[\frac{a_{n+1}}{n+1}=\frac{a_{n}}{n}-\frac{a_{n-1}}{n-1}\]
这个我懒得给过程了,最后得到
\[a_{n}=nsin(\frac{n{\pi}}{3}+\frac{\pi}{6})\]

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其妙 Posted at 2013-10-13 14:59:55
回复 3# 战巡
牛笔!原来是那个著名的周期为6的数列啊!特征根为复数。
妙不可言,不明其妙,不着一字,各释其妙!

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