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[不等式] 三元不等式一条

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v6mm131 posted 2017-8-15 15:54 |Read mode
若$a,b,c>0$,满足$a^2+b^2+c^2=1$证明:\[\frac{a}{1-ab}+\frac{b}{1-bc}+\frac{c}{1-ca}\le \frac{3\sqrt{3}}{2}\]

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其妙 posted 2017-8-15 18:31
k神的链接也会来了!
不过我先丢一个链接再说:blog.sina.com.cn/s/blog_54df069f0102x8z7.html

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色k posted 2017-8-15 22:16
回复 2# 其妙

这个我没链接
刚才我也想过用抛物线来切,大概和你给的链接差不多,还好还没下笔。

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其妙 posted 2017-8-16 00:00
我似乎在人教论坛看见何版证明过的一道题,找不到了
暂时搜查到一道类似题(其实也不类似):bbs.pep.com.cn/forum.php?mod=viewthread&t … 121&extra=page=7
妙不可言,不明其妙,不着一字,各释其妙!

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kuing posted 2017-8-16 00:09
回复 4# 其妙

这个确实不类似,而且简单多了,撸题集里也有链接(1032页,而下一页可能就有你说的何版那个)。

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hbghlyj posted 2025-3-21 04:10
其妙 发表于 2017-8-15 16:00
我似乎在人教论坛看见何版证明过的一道题,找不到了
暂时搜查到一道类似题(其实也不类似):http://bbs.pe ...
图片失效了!

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爪机专用 posted 2025-3-21 04:46
Last edited by kuing 2025-3-21 20:47我当时 5# 说《撸题集》P.1032 有链接,我看了下,估计 4# 失效的图片是这个题:artofproblemsolving.com/community/c6h109029
If $ a^{2} + b^{2} + c^{2} = 1,a,b,c \ge 0$, Then:
$ \frac {1}{1 - ab} + \frac {1}{1 - bc} + \frac {1}{1 - ca}\le \frac {9}{2}$
这个确实简单
I am majia of kuing

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爪机专用 posted 2025-3-21 04:54
4#丢的图不重要,倒是2#的博客链接已经看不到内容,当时3#还庆幸没下笔,看来还是得下……
I am majia of kuing

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