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上有 \overbrace 下有 \underbrace ，左右直接 \left\{ \right\} ，没想到竟然会有倾斜的需要。
问题来自：bbs.ctex.org/forum.php?mod=viewthread&tid=154759，要输出这样的公式：
这么难搞的东西还是上 tikz 吧，测试代码：- \documentclass{ctexart}
- \usepackage{amsmath}
- \usepackage{tikz}
- \usetikzlibrary{decorations.pathreplacing}
- \newcommand\tikzmark[2][0,0]{%
- \tikz[baseline,remember picture,overlay]
- \coordinate (#2) at (#1);}
- \begin{document}
- $k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个
- \[
- A_{km}(x)=2^{
- \tikzmark[0pt,4.5pt]{C1}
- 2^{2^{\cdot^{\cdot^{\cdot^{
- \tikzmark[2pt,4pt]{C2}
- 2^{x^{
- \tikzmark[0pt,3.5pt]{C3}
- 2^{2^{\cdot^{\cdot^{\cdot^{
- \tikzmark[2pt,4pt]{C4}
- 2}}}}}}}}}}}}},
- B_k(y)=4^{
- \tikzmark[0.5pt,4pt]{B1}
- 4^{4^{\cdot^{\cdot^{\cdot^{
- \tikzmark[2pt,4pt]{B2}
- 4^y}}}}}}.
- %
- \tikz[remember picture,overlay]
- {
- \draw[decorate,decoration=brace]
- (C1)--node[shift={(135:8pt)}]{$\scriptstyle k\text{个}$}(C2);
- \draw[decorate,decoration=brace]
- (C3)--node[shift={(135:8pt)}]{$\scriptstyle m\text{个}$}(C4);
- \draw[decorate,decoration=brace]
- (B1)--node[shift={(135:8pt)}]{$\scriptstyle k\text{个}$}(B2);
- }
- \]
- $k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个$k$个
- \end{document}
效果：
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青青子衿
发表于 2019-7-7 12:45
