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[不等式] 较易的两道题

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Shiki Posted 2019-9-29 22:03 |Read mode
1.$a=\sqrt {x^2-xy+y^2},b=p\sqrt{xy},c=x+y.$以它们为边长可以构成一个三角形,求p的范围
2.已知$(2xy-1)^2=(5y+2)(y-2)$
求$$x-\frac{1}{2y}$$
的最小值
= =

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kuing Posted 2019-9-29 22:15

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