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[函数] 群友的一函数不等式题

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力工 posted 2020-12-5 19:05 |Read mode
人叫裙群友鄂#山@角(7%¥#*39)  11:20:11这个如何解决?对面的大佬看过来吧
已知$1<x\leqslant 2$,证明:
$x(x-1)2^{x-3}\leqslant 2^x-x-1\leqslant \dfrac{x(x-1)}{2}$.

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