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$\int \sqrt{1+\sqrt{1+x^2}} \rmd x$

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hbghlyj Posted at 2024-6-3 18:37:08 |Read mode
integral-calculator.com 无法算出$\int \sqrt{1+\sqrt{1+x^2}} \rmd x=\frac{2 x}{\sqrt{\sqrt{x^2+1}+1}}+\frac{2 x^3}{3 \left(\sqrt{x^2+1}+1\right)^{3/2}}$

Rubi rule 2154: 当$a^2=b^2c$时,$$\int \sqrt{a+b \sqrt{c+d x^2}} \, dx=\frac{2 b^2 d x^3}{3 \left(a+b \sqrt{c+d x^2}\right)^{3/2}}+\frac{2 a x}{\sqrt{a+b \sqrt{c+d x^2}}}$$

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三个参数就够了,而且参数d与微分算符d还不加以区分😕  Posted at 2024-6-4 01:18

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 Author| hbghlyj Posted at 2024-6-3 18:40:40
当$a^2$不等于$b^2c$时,积分没有这种简单形式了

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2025-4-20 22:09 GMT+8

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