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[函数] 一小道同构题

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1+1=? posted 2025-3-26 09:09 from mobile |Read mode
Last edited by hbghlyj 2025-3-26 09:16已知函数 $f(x)=\frac{e^a(\ln x+x+1)-a}{x}(a \inR)$.
  • 证明 $f(e^a) \geq 2+a+\frac{4 a^2}{3}$;
  • 若 $f(x) \leq e^{x-a}$ 恒成立,求 $a$ 的取值范围.

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original poster 1+1=? posted 2025-3-26 09:10 from mobile
第二问有超越取等点
1+1=2吗?

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