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想把里面的汉子不斜体化怎么破

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琉璃幻 Posted at 2014-9-5 06:52:34 |Read mode
\[1\cdot\left(1+\frac{1}{n}\right)^n<\left(\underbrace{1+1+\cdots+1}_\textit{n+1 个 }+\underbrace{\frac{1}{n}+...+\frac{1}{n}}_\textit{n个}\right )^{n+1}\Big/(n+1)^{n+1}=\left(\frac{n+2}{n+1}\right)^{n+1}=\left(1+\frac{1}{n+1} \right )^{n+1}\]

@kuing

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kuing Posted at 2014-9-5 09:33:31
擦啊,它之所以会斜,是因为你自己用了斜体命令啊
你的命令:\underbrace{1+1+\cdots+1}_\textit{n+1 个 }
\textit 就是斜体的意思,所以它里面的东西自然都变成斜体
正确的方法应该是用 \text 切换到文本模式,然后再对 n+1 用 \$ ,效果如下
\[右键查看代码 \to \underbrace{1+1+\cdots+1}_{\text{$n+1$个}}\]

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isee Posted at 2014-9-6 08:14:43
好一个汉子

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 Author| 琉璃幻 Posted at 2014-9-6 14:26:59
回复 2# kuing

Merci!

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kuing Posted at 2014-9-6 16:40:49
回复 4# 琉璃幻

这又是什么文……

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kuing Posted at 2014-9-6 16:43:34
\[
1\cdot\left(1+\frac1n\right)^n<\biggl({\underbrace{1+1+\cdots+1}_{\text{$n+1$个}}}+{\underbrace{\frac1n+\frac1n+\cdots+\frac1n}_{\text{$n$个}}}\biggr)^{n+1}\bigg/(n+1)^{n+1}=\left(\frac{n+2}{n+1}\right)^{n+1}=\left(1+\frac1{n+1} \right)^{n+1}
\]

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战巡 Posted at 2014-10-21 07:44:25
回复 5# kuing


鸟语(法语)
谢谢之意

特么我其他群里有几个学法语的混球三天两头发鸟语,这个词发的最多,所以认识

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大羊系列 Posted at 2014-10-21 10:41:38
为毛不用上括号和下括号共同使用?不是更明显么。。。

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2025-4-21 01:46 GMT+8

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