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证明有关正态分布的pdf的等式

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opuikl_0 Posted at 2017-5-1 04:58:09 |Read mode
证明下面这个等式成立:
2F84EE2F-409C-45DA-AE5B-76EA7B19DC37.gif
这里的 $\phi$ 是 $N(0,1)$ 的 pdf.

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战巡 Posted at 2017-5-1 06:51:07
回复 1# opuikl_0


....
为什么这还要问?
带进去硬算不就完了么,又不是什么很复杂的东西

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 Author| opuikl_0 Posted at 2017-5-1 07:22:32
回复 2# 战巡

额 我尝试代入到pdf的指数形式里面去算过,算不出相等啊。。

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战巡 Posted at 2017-5-1 08:16:16
怎么会不等呢?真是服了你了
\[\phi(-\frac{\ln(m)}{\sqrt{v}}+\frac{\sqrt{v}}{2})=\frac{1}{\sqrt{2\pi}}\exp(-\frac{1}{2}[-\frac{\ln(m)}{\sqrt{v}}+\frac{\sqrt{v}}{2}]^2)\]
\[=\frac{1}{\sqrt{2\pi}}\exp(-\frac{1}{2}[(\frac{\ln(m)}{\sqrt{v}}+\frac{\sqrt{v}}{2})-\frac{2\ln(m)}{\sqrt{v}}]^2)\]
\[=\frac{1}{\sqrt{2\pi}}\exp(-\frac{1}{2}[(\frac{\ln(m)}{\sqrt{v}}+\frac{\sqrt{v}}{2})^2-\frac{4\ln(m)}{\sqrt{v}}(\frac{\ln(m)}{\sqrt{v}}+\frac{\sqrt{v}}{2})+(\frac{2\ln(m)}{\sqrt{v}})^2])\]
\[=\frac{1}{\sqrt{2\pi}}\exp(-\frac{1}{2}[(\frac{\ln(m)}{\sqrt{v}}+\frac{\sqrt{v}}{2})^2-2\ln(m)])\]

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 Author| opuikl_0 Posted at 2017-5-1 08:59:16
回复 4# 战巡

明白了!谢谢!

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2025-4-21 01:21 GMT+8

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