Forgot password?
 Register account
View 2231|Reply 0

[不等式] 一道样子不错的6元不等式

[Copy link]

29

Threads

53

Posts

675

Credits

Credits
675

Show all posts

wanhuihua Posted 2017-10-22 17:01 |Read mode
Last edited by hbghlyj 2025-3-19 20:16设 $a, b, c, x, y, z$ 为正数
求证
\[
\frac{b+c}{a(y+z)}+\frac{a+c}{(z+x) b}+\frac{a+b}{(x+y) c} \geq 3 \frac{a+b+c}{a x+b y+c z}
\]

Mobile version|Discuz Math Forum

2025-6-6 14:42 GMT+8

Powered by Discuz!

× Quick Reply To Top Edit