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[不等式] 一道样子不错的6元不等式

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wanhuihua posted 2017-10-22 17:01 |Read mode
Last edited by hbghlyj 2025-3-19 20:16设 $a, b, c, x, y, z$ 为正数
求证
\[
\frac{b+c}{a(y+z)}+\frac{a+c}{(z+x) b}+\frac{a+b}{(x+y) c} \geq 3 \frac{a+b+c}{a x+b y+c z}
\]

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