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$ ⟨x⟩ = RxR$反例
Example 2.7.
In the ring $M_2 (\mathbb{F})$ put\[ A \coloneqq\left(\begin{array}{cc}
1 & 0\\
0 & 0
\end{array}\right) \text{ and } P \coloneqq\left(\begin{array}{cc}
0 & 1\\
1 & 0
\end{array}\right) \text{ so that } A + PAP = \left(\begin{array}{cc}
1 & 0\\
0 & 1
\end{array}\right) \]
Then $1_2 = A + PAP \in \langle A \rangle$, but $A$ is not invertible so none of the matrices in $M_2 (\mathbb{F})$ is invertible, and hence $M_2
(\mathbb{F}) AM_2 (\mathbb{F})$ is not a subgroup and $\langle A \rangle
\neq M_2 (\mathbb{F}) AM_2 (\mathbb{F})$. $\Box$
If there is $x \in R$ such that $I = \langle x \rangle$ then we say $I$ is principal and is generated by $x$. They are lines in vector space. | ringsandmodulespartsIandII
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PS: 我发现LaTeX符 $+$, $=$, $\ne$, $\in$ 在此 pdf 中进行了修改(缩小)
PPS: 刚发现attachimg可以放在链接里(单击图像将转到 url) |
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