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[几何] 已知$A,B,C$共线且$AB:BC=r_1:r_2$,求作一点$P$,使得$PA:PC=r_1:r_2$

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abababa Posted at 2023-3-24 21:11:34 |Read mode
Last edited by abababa at 2023-3-24 21:31:00如题,已知$A,B,C$共线且$AB:BC=r_1:r_2$,求作一点$P$,使得$PA:PC=r_1:r_2$。

这个作出来,应该是$PB$为$\triangle PAC$的角平分线吧,具体要怎么做?

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我说我怎么能看懂,原来不是 hbghlyj 发的  Posted at 2023-3-24 22:58

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kuing Posted at 2023-3-25 00:20:15
不就是阿氏圆吗?

PS、
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isee         我说我怎么能看懂,原来不是 hbghlyj 发的

😂😂😂

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 Author| abababa Posted at 2023-3-25 16:24:23
kuing 发表于 2023-3-25 00:20
不就是阿氏圆吗?

PS、
原来如此。以前听说过阿氏圆,但一直没有仔细去了解过。

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