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[几何] 分线段成比例定理

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hbghlyj Posted 2023-3-13 19:14 |Read mode
The Rule of Four Quantities: $\frac{\sin \overparen{B D}}{\sin \overparen{C E}}=\frac{\sin \overparen{A D}}{\sin \overparen{A E}}$ FADEBC
证明:
因为$\sin\overparen{BF}=\sin\overparen{CF}=1$
对$\triangle DEF$的截线$ABC$用Menelaus定理$\frac{1}{\sin \overparen{C E}}=\frac{1}{\sin \overparen{B D}} \cdot \frac{\sin \overparen{A D}}{\sin \overparen{A E}}\hskip1em$ $_\square$
Spherical Trigonometry Through the Ages - Lauren Roberts - 4.1 The Rule of Four Quantities

Heavenly Mathematics: The Forgotten Art of Spherical Trigonometry - Princeton (2012) - Glen Van Brummelen - Chapter 4 page 60

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