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[几何] 正方体的三视图

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郝酒 Posted at 2014-1-6 21:20:17 |Read mode
最少需要几个正方体(可悬空),使其三视图均为3*3的方格。
此题该如何考虑啊?〇一规划吗?

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kuing Posted at 2014-1-6 21:39:49
8个应该就可以了,再由任一视图的边上正方形都至少需要有一个,所以至少8个,等我画画图看看先。

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kuing Posted at 2014-1-6 21:45:19
QQ截图20140106214831.jpg

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 Author| 郝酒 Posted at 2014-1-6 22:02:31
谢谢!构造方法有没有一定的规则?:)
一共有多少种不同的摆法?

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kuing Posted at 2014-1-6 22:04:57
来个会动的

备用图
6273b251gw1eca684mpvwg20hg0aealh.gif

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kuing Posted at 2014-1-6 22:11:30
回复 4# 郝酒

好像就只有这种样子的了,其他的都通过旋转或对称变成这种。

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证明唯一还不太好说

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 Author| 郝酒 Posted at 2014-1-6 22:16:32
cool~
多谢,在carib中 ,你是如何把悬空的正方体摆出来的呢?

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kuing Posted at 2014-1-6 22:39:28
回复 7# 郝酒

先放27个正方体组成魔方,放的时候可以粘着放的,然后将不需要的隐藏掉。

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