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[数论] 存在无穷多素数p使-1modp二次剩余

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hbghlyj posted 2023-5-2 23:32 |Read mode

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存在无穷多素数$p$使$(\frac{-1}p)=-1$
(较难) 存在无穷多素数$p$使$(\frac{-1}p)=1$

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$-1$ 是奇素数 $p$ 二次剩余的充要条件就是 $p\equiv 1\pmod 4$ 吧 posted 2023-6-5 13:48

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