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[数论] $f(x)$不可约,且整除$f(x^2)$

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hbghlyj Posted 2023-11-1 04:47 |Read mode
Last edited by hbghlyj 2025-5-16 04:38在 \(\mathbb{F}_2\) 上,$f(x) = x^2 + x + 1$ 不可约,且
$$
f(x^2) = (x^2 + x + 1)^2
$$

在 \(\mathbb{Q}\) 上,$f(x) = x^4 + x^3 + x^2 + x + 1$ 不可约,且
$$
f(x^2) = x^8 + x^6 + x^4 + x^2 + 1
      = f(x)\,(x^4 - x^3 + x^2 - x + 1)
$$

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 Author| hbghlyj Posted 2025-5-16 04:38

两个问题:

在$\mathbb F_q$上是否存在$f(x)$不可约多项式,且整除$f(x^2)$?
在$\mathbb F_q$上是否存在$f(x)$不可约多项式,且整除$f(x^3)$?

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