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[几何] △ABC外接圆上一点关于切△ABC的所有抛物线的两条切线形成一个线束对合

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hbghlyj Posted at 14 hr ago |Read mode
Last edited by hbghlyj at 8 hr ago△ABC外接圆上任意点P,抛物线p1,p2,p3与△ABC三边相切,求证:P到p1,p2,p3的切线形成一个线束对合

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lxz2336831534 Posted at 13 hr ago From the mobile phone
图片太小看不出来 ,

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遇到的TeX问题已发至tex.stackexchange.com  Posted at 11 hr ago

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lxz2336831534 Posted at 13 hr ago From the mobile phone
看题目估计是,笛沙格对合定理的对偶形式,三角形abc是退化的四线形,抛物线是四线二次线簇的一个元素,根据笛沙格对合定理,切线皆对合。

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数学问题已发至math.stackexchange.com  Posted at 7 hr ago

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 Author| hbghlyj Posted at 12 hr ago
lxz2336831534 发表于 2025-4-20 02:18
三角形abc是退化的四线形,抛物线是四线二次线簇的一个元素

应该是与三角形的三边及无穷远线这四线相切。

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 Author| hbghlyj Posted at 12 hr ago
P不在△ABC外接圆上也成立吧?

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 Author| hbghlyj Posted at 11 hr ago

当P在△ABC外接圆上,该对合恰好为等角线?

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2025-4-20 22:23 GMT+8

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