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[几何] 堆球问题的半径

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青青子衿 posted 2022-9-5 10:21 |Read mode
Last edited by 青青子衿 2022-9-5 11:02现有七个球如图所示,在它们间隙位置放六个球构成第二层,使得第二层的任意一个球与第一层的三个球相切。
当这六个球的相邻两个相切时,这六个球的半径是多少?
95722080.jpg

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战巡 posted 2022-9-5 11:14
考察以下就知道了,这玩意是对称的,比如看图中1、6、5、15号这4个球,如果在上面叠两个,且这两个相切,那其切点的垂直投影,必然在6号和15号球球心连线上

也就是说明这个球垂直往下的投影(就是个圆),刚好是支撑这个球的下层三个球球心构成的三角形的内切圆

如此说明,如果下面的球半径为$R$,上面的就是
\[r=\frac{R}{\sqrt{3}}\]

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