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[函数] 三角函数恒等式

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hbghlyj Posted 2024-10-24 17:03 |Read mode
Last edited by hbghlyj 2025-3-3 06:22证明恒等式:\begin{multline}\frac{\cos4A}{\sin A\sin(A-B)\sin(A-C)}\\+\frac{\cos4B}{\sin B\sin(B-A)\sin(B-C)}\\+\frac{\cos4C}{\sin C\sin(C-A)\sin(C-B)}\\=8\sin(A+B+C)+\csc A\csc B\csc C\end{multline}
wolframalpha.com/input?i=(cos(4*A)/(sin(A)*si … sc(A)*csc(B)*csc(C))

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ZCos666 Posted 2025-2-28 23:30
等价于恒等式
\[ \sum\dfrac{(x^8+1)yz}{x(x^2-1)(x^2-y^2)(x^2-z^2)}=xyz-\dfrac{1}{xyz}+\dfrac{2xyz}{(x^2-1)(y^2-1)(z^2-1)} \]

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 Author| hbghlyj Posted 2025-3-3 06:27
可以推广吗

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