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[不等式] 一道很松的不等式

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lxz2336831534 Posted at 2024-7-4 22:29:51 |Read mode
Last edited by hbghlyj at 2025-4-10 16:53:23\[
\begin{aligned}
& \forall x>0, \mathrm{e} \geq y>1 \\
& 1+\ln x+x y-y \ln y \geq x \ln y+y \ln x
\end{aligned}
\]
如题,有什么简单方法吗

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Czhang271828 Posted at 2024-7-4 22:41:52
使用 $\ln x\mapsto (x-1)$ 加强不等式 (左侧增加得少, 右侧增加得多), 得
$$
x+y\geq (x+y)\ln y.
$$

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2025-4-21 14:34 GMT+8

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