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[不等式] 比较大小 $a=1/10,b=\ln\frac{10}9,c=\frac{\sqrt{10}}{30}$

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isee posted 2024-12-29 13:19 |Read mode
Last edited by isee 2024-12-29 13:59将以下面三数 $a=1/10,b=\ln\frac{10}9,c=\frac{\sqrt{10}}{30}$ 从小到大排序.
isee=freeMaths@知乎

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Aluminiumor posted 2024-12-29 13:49 from mobile
显然 $a<b,a<c$
$b=\ln(10/9)<\sqrt{10/9}-\sqrt{9/10}=c$
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