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[不等式] 二元对称多项式的最小值点不在边界上,有低于4次的例子吗

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hbghlyj Posted 2024-12-27 02:30 |Read mode
二元对称多项式$F(x,y)$在区域$0\le x\le y\le 1$上的最小值点不在其边界上。
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4次的例子,$F(x,y)=\left[\left(x-\frac{1}{3}\right)^2+\left(y-\frac{2}{3}\right)^2\right]\cdot\left[\left(x-\frac{2}{3}\right)^2+\left(y-\frac{1}{3}\right)^2\right]$
Screenshot 2024-12-26 194955.png
问题:有低于4次的例子吗?

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爪机专用 Posted 2024-12-27 03:15
低于四次,那整理成关于 p=x+y 与 q=xy 的式子后,q 最多一次,固定 p,则当 q 取最值时原式取最值,而 q 取最值要么 x=0 要么 x=y,都在边界。
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 Author| hbghlyj Posted 2024-12-27 03:17
好像稍微有点问题如 $(x + y) (-3 + 2 x + 2 y)$ 最小值在$x+y=\frac34$上

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 Author| hbghlyj Posted 2024-12-27 03:18
解决了👌

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