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[函数] 导数证明

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ruichen posted 2019-6-30 16:20 |Read mode
Last edited by hbghlyj 2025-3-10 19:39己知函数 $f(x)=x \ln x-a x$ ($x>0$)
1)当 $a=e$ 时,求证:$f(x) \leq \frac{x^2}{e}-x$
2)若存在 $0<x_1<x_2$ 使得 $f(x_1)+f(x_2)=0$ 求证:$e^a+\sqrt{x_1 x_2}>x_1+x_2$

第一问应该恒成立问题 是不是移项构造函数  再求导数

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