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[不等式] 一个三元不等式

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力工 Posted 2023-4-21 22:55 |Read mode
已知实数$x,y,z$满足$x+y+z=2,xy+yz+zx=1$,求$xyz$的最大值。
我本想从构造三次函数的角度做,没能完成。

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kuing Posted 2023-4-21 23:09
构造三次函数是可以的啊,设 `f(t)=(t-x)(t-y)(t-z)=t^3-2t^2+t-xyz`,当 `xyz` 变化时,`f(t)` 上下移动,而又得确保三个根均为实数,临界点就是 `f(t)` 与 `x` 轴相切时……

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我是说渣唔没算出来。  Posted 2023-4-22 11:06

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kuing Posted 2023-4-22 11:59
pqr 定理就是这样推的:cut-the-knot.org/arithmetic/algebra/3variable.pdf

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谢谢!原来昨天代错了,唉,弄了半天,今天才发现!  Posted 2023-4-22 12:05

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