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[几何] 一道双曲线计算题

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271828 posted 2014-4-18 21:34 |Read mode
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original poster 271828 posted 2014-4-18 21:35
看看大家有没有简单一点的方法。

答案是 $\frac{4}{5}\sqrt{10}$

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等待hxh posted 2014-4-19 16:26
此题是本人改自2013南通二模14题而命的一题,硬算去解比较麻烦,原本给文理科的16题是这样的,但文科太简单,换了一题。

此题方法很多

此题方法很多

此题暴力解繁琐

此题暴力解繁琐

原本文科题是这个

原本文科题是这个

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original poster 271828 posted 2014-4-19 17:18
那就是说,只能硬算了啊?

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等待hxh posted 2014-4-19 17:32
方法选取得当计算量要小很多,不过常规思路,还真的得算,刚开始不建议把此题给学生做的! 参考此题解法 blog.sina.com.cn/s/blog_c50749e40101di8a.html

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其妙 posted 2014-4-19 18:01
弦中垂线和坐标轴的交点的结论可做吧,运算是有点麻烦

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original poster 271828 posted 2014-4-19 18:59
这道题最近很火啊

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踏歌而来 posted 2014-4-26 22:35
回复 5# 等待hxh

请问,在解法三(向量法)中,
$(x1+1)^2+(\frac{1}{x1}-1)^2=(x2+1)^2+(\frac{1}{x2}-1)^2$
怎样化简成
$ \frac{1}{x1}+\frac{1}{x2}=x1+x2+2?$
我在化简时,约掉了一个(x1-x2),但随后没有这个结果。
请赐教!

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等待hxh posted 2014-4-26 22:46

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其妙 posted 2014-4-26 23:41
回复 9# 等待hxh
博客图片.jpg
妙不可言,不明其妙,不着一字,各释其妙!

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踏歌而来 posted 2014-4-27 21:05
Last edited by 踏歌而来 2014-4-27 21:53谢谢两位,我想问的就是南通二模十四题。

等待hxh,也是我的偶像,第七个偶像。
解析几何是难玩的,能玩得这么好,令我敬佩!

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踏歌而来 posted 2014-4-28 09:33
kk.JPG

点差法用不上;
$用Kad·Kbc=-1,结果同AC=AB没化简时的情况。$
$又考虑了AB=BC,结果出现了\frac{2}{x1x2}更复杂的情况。$

请大家帮我看看,图中的化简结果是如何得到的?

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踏歌而来 posted 2014-4-28 17:08
看来,这个化简挺难的,要用到 等待hxh的秘密武器。

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其妙 posted 2014-5-2 19:35
妙不可言,不明其妙,不着一字,各释其妙!

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