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[几何] 抛物线中的三直线与椭圆相切的充要条件

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lemondian posted 2021-4-6 10:53 |Read mode
求助,这个如何证明?
已知椭圆$\dfrac{x^2}{m^2}+\dfrac{y^2}{n^2}=1$与抛物线$y=ax^2+bx+c(a\ne0)$,$A,B,C$为抛物线上任意三点,若直线$AB,AC$均与椭圆相切,则直线$BC$也与椭圆相切的充要条为$(am^2+c)^2=b^2m^2+n^2$。

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