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[几何] 以△一边上的中点作圆,以这边上的任意顶点作圆,证两圆交点相关连线与这边垂直

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zhiwen posted 2023-11-19 22:00 |Read mode

已知:△ABC,BC中点D。⊙D(DB)交AB、AC于E、F,⊙B(BE)交⊙D于G,FG交BC于H。
求证:AH⊥BC

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乌贼 posted 2023-11-20 00:37
证$ \angle EBD=\angle GBD=\angle CFH $,得$ ABHF $四点共圆即可

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