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[不等式] 我也问一道$\sum\frac1{\sqrt{a^2-3a+3}}\le3$

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kuing Post time 2015-3-7 01:07 |Read mode
$a$, $b$, $c>0$, $a+b+c=3$, show that
\[ \frac1{\sqrt{a^2-3a+3}}+\frac1{\sqrt{b^2-3b+3}}+\frac1{\sqrt{c^2-3c+3}}\leqslant3. \]

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 Author| kuing Post time 2015-3-8 16:28
有木有银???

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Tesla35 Post time 2015-3-8 23:07
回复 2# kuing


    木有。都去过节了。

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睡仙 Post time 2015-3-13 13:34
一步法可以搞定

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其妙 Post time 2015-3-15 16:06
一步法可以搞定
睡仙 发表于 2015-3-13 13:34

县长的招牌!,怎么不来宣传一下你建立的群?

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睡仙 Post time 2015-3-16 16:10
回复 5# 其妙


    欢迎加入不等式天堂:  94462317

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睡仙 Post time 2015-3-16 23:27
回复 6# 睡仙

今天下午我们又给出了另一个包力型的证明

手机版|悠闲数学娱乐论坛(第3版)

2025-3-6 02:00 GMT+8

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